In the common emitter configuration of n-p-n transistor `10^(10)` electrons enter the emitter in 1`mus` and 2% of the electrons are lost of the base.

Question

In the common emitter configuration of n-p-n transistor `10^(10)` electrons enter the emitter in 1`mus` and 2% of the electrons are lost of the base.

In the common emitter configuration of n-p-n transistor `10^(10)` electrons enter the emitter in 1`mus` and 2% of the electrons are lost of the base. The current gain of the amplifier is
A. 2
B. 98
C. 1
D. 49

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`I_(b)=2% ` of ` I_(e), I_(c)=90% ` of `I_(e), beta=?`
`beta=(I_(c))/(I_(b))=(98% " of " I_(e))/(2% " of " I_(b))=49`

4 views Answered 2023-02-05 15:29