The transistor working as common base amplifier, current gasin is 0.97 and base current is 0.12 mA.
The transistor working as common base amplifier, current gasin is 0.97 and base current is 0.12 mA.
A. 5 mA
B. 3.88 mA
C. 3 mA
D. 0.12 mA
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Correct Answer - A
`alpha=(I_(c))/(I_(e))=(I_(c))/(I_(c)+I_(b))`
`therefore I_(c)=alpha(I_(c)+I_(b))`
`therefore I_(c)=(I_(b))/(1-alpha)=(0.12)/(1-0.97)=3.88 mA`
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