In a common emitter transistor amplifier, the output resistance is `500Omega` and the current gain `beta=49`. If the power gain of the amplifier is `5

Question

In a common emitter transistor amplifier, the output resistance is `500Omega` and the current gain `beta=49`. If the power gain of the amplifier is `5

In a common emitter transistor amplifier, the output resistance is `500Omega` and the current gain `beta=49`. If the power gain of the amplifier is `5xx10^(6)`, the input resistance is
A. `325Omega`
B. `165Omega`
C. `198Omega`
D. `240Omega`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Given, `R_(o)=500kOmega, beta=49 and P=5xx10^(6)`
We have, `P=beta^(2)(R_(o))/(R_(i))`
`5xx10^(6)=((49)^(2)xx500 xx 10^(3))/(R_(i))`
`R_(i)=(49xx49xx500)/(5xx10^(6))=240Omega`

5 views Answered 2023-02-05 15:29