A p-n-p transistor is used as common base amplifier as `V_(eb) =3V` . When its emitter current changes from 13.4 mA to 20.14 mA its collector current

Question

A p-n-p transistor is used as common base amplifier as `V_(eb) =3V` . When its emitter current changes from 13.4 mA to 20.14 mA its collector current

A p-n-p transistor is used as common base amplifier as `V_(eb) =3V` . When its emitter current changes from 13.4 mA to 20.14 mA its collector current changes from 13.4 mA to 19.9 mA. Its current gain will be
A. 9.849
B. 0.8489
C. 98.49
D. 0.9849

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`V_(eb)=3V`,
`deltaI_(e)=20.15-13.55=6.6 mA`
`deltaI_(c)=19.9-13.4=6.5 mA`
`alpha=?`
Now `alpha=(deltaI_(c))/(deltaI_(e))`
`=(6.5)/(6.6)=0.9849`

5 views Answered 2023-02-05 15:29