For the reaction `2NO_(2)O_(5 ) to 4NO_(2)+O_(2)` rate and rate constant are `1.22xx10^(-4) and 3.4 xx10^(-5) S^(-1)` respectively then the concentrat

Question

For the reaction `2NO_(2)O_(5 ) to 4NO_(2)+O_(2)` rate and rate constant are `1.22xx10^(-4) and 3.4 xx10^(-5) S^(-1)` respectively then the concentrat

For the reaction `2NO_(2)O_(5 ) to 4NO_(2)+O_(2)` rate and rate constant are `1.22xx10^(-4) and 3.4 xx10^(-5) S^(-1)` respectively then the concentration of `N_(2) O_(5) ` at that time will be
A. `1.732`
B. `3.5`
C. `1.02xx10^(-4)`
D. `3.4xx10^(5)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`[N_(2)O_(5)] =["Rate "] =(1.22xx10^(-4))/(3.4xx10^(-5))=(12.2)/(3.4)=3.5`

5 views Answered 2023-02-05 15:29