The formation of `SO_(3) ` from ` SO_(2) and O_(2) ` takes place in the following steps : `(i) SO_(2)+2NO_(2) to 2SO_(3)+2NO` `(ii) 2NO +O_(2) to 2NO_

Question

The formation of `SO_(3) ` from ` SO_(2) and O_(2) ` takes place in the following steps : `(i) SO_(2)+2NO_(2) to 2SO_(3)+2NO` `(ii) 2NO +O_(2) to 2NO_

The formation of `SO_(3) ` from ` SO_(2) and O_(2) ` takes place in the following steps :
`(i) SO_(2)+2NO_(2) to 2SO_(3)+2NO`
`(ii) 2NO +O_(2) to 2NO_(2)`
A. `NO_(2) ` is intermediate
B. `NO ` is catalyst
C. `NO_(2) ` is catayst and `NO ` is intermediate
D. `NO` is catalyst and `NO_(2) ` is intermediate

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
The reactants first combine with the catalyst to form an intermediate complex which is short lived and decomposes to form the product and regenerating the catalyst hence NO is intermediate complex and `NO_(2)` is the catalyst .

4 views Answered 2023-02-05 15:29