The rate of formation of a dimer in a second order dimerization reaction is `9.5 xx 10^(-5) mol L^(-1) s^(-1)` at `0.01 mol L^(-1)` monomer concentrat

Question

The rate of formation of a dimer in a second order dimerization reaction is `9.5 xx 10^(-5) mol L^(-1) s^(-1)` at `0.01 mol L^(-1)` monomer concentrat

The rate of formation of a dimer in a second order dimerization reaction is `9.5 xx 10^(-5) mol L^(-1) s^(-1)` at `0.01 mol L^(-1)` monomer concentration. Calculate the rate constant.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

According to the available data,
rate(r ) =`9.5 xx 10^(-5) mol L^(-1)s^(-1) , [A]=0.01 mol L^(-1)`.
`therefore` rate( r) =`k[A]^(2)` or `k=("rate")/([A])^(2) = (9.5 xx 10^(-5)mol L^(-1)s^(-1))/(0.01 mol L^(-1))^(2) = 0.95 L mol^(-1)s^(-1)`

5 views Answered 2023-02-05 15:29