In a hydrogen atom,an electron revolves with a frequency of `6.8xx10^(9)`MHz in an orbit of diameter 1.06 Å.The equivalent magnetic moment is

Question

In a hydrogen atom,an electron revolves with a frequency of `6.8xx10^(9)`MHz in an orbit of diameter 1.06 Å.The equivalent magnetic moment is

In a hydrogen atom,an electron revolves with a frequency of `6.8xx10^(9)`MHz in an orbit of diameter 1.06 Å.The equivalent magnetic moment is
A. `9.5xx10^(-22) Am^(2)`
B. `7.5xx10^(-10 Am^(2)`
C. `4.5xx10^(-24) Am^(2)`
D. `9.5xx10^(-24) Am^(2)`

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
F=`6.8xx10^(9) MHZ,r=0.53 A^(@),M=?`
M=IA
`=qfpir^(2)`ltbrge`1.6xx10^(-19)xx6.8xx10^(9)xx10^(6)xx3.14xx(0.53xx10^(-10))^(2)`
`=9.5xx10^(-24)Am^(2)`

8 views Answered 2023-02-05 15:29