An electron in the hydrogen atom circles around the proton with a speed of `2.18xx10^(6)`m/s in an orbit of radius `0.53Å` . The equivalent current is

Question

An electron in the hydrogen atom circles around the proton with a speed of `2.18xx10^(6)`m/s in an orbit of radius `0.53Å` . The equivalent current is

An electron in the hydrogen atom circles around the proton with a speed of `2.18xx10^(6)`m/s in an orbit of radius `0.53Å` . The equivalent current is
A. `1.048xx10^(-2)A`
B. `1.048xx10^(-3)A`
C. `1.048xx10^(-4)A`
D. `1.058xx10^(-4)A`

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

Related Questions

a proton enters a perpendicular magnetic field of intensity b with speed v the proton moves along a circular path of radius r if a deuteron enter into the same magnetic field with same speed the radius of the circular trajectory will be

2 Answers 5 Views

The electron in hydrogen atom moves with a speed of `2.2xx10^(6)m//s` in an orbit of radius `5.3xx10^(-11)cm`. Find the magnetic moment of the orbitin

2 Answers 4 Views

Determine the radius of the first orbit of the hydrogen atom. What would be the velocity and frequency of the electron in the first orbit ? Given : `h

2 Answers 4 Views

Classically, an electron can be in any orbit around the nucleus of an atom. Then what determines the typical atomic size? Why is an atom not, say, tho

2 Answers 4 Views

Asatellite is launched into a circular orbit of radius R around the earth. A second satellite is launched into an orbit of radius (1.04) R. Then the p

2 Answers 8 Views

A `H_(2)` atom consits of a proton and an electron that revolves in a circular orbit around the proton with a radius of `5.3xx10^(-9)cm`. If the elect

2 Answers 5 Views

In a hydrogen atom the electrons revolves round the nucleus `6.8xx10^(15)` times per second in a n orbit of radius 0.53 Å.Determine its equivalent mag

2 Answers 4 Views

The electron in the hydrogen atom is moving with a speed at `2.3xx10^(6) m//s`in an orbit of radius 0.53 Å.The magnetic of the revolving electron is

2 Answers 9 Views

In a hydrogen atom,an electron revolves with a frequency of `6.8xx10^(9)`MHz in an orbit of diameter 1.06 Å.The equivalent magnetic moment is

2 Answers 8 Views

An electron in an atom revolves the nucleus in an orbit of radius 0.53 Å equivalent magnetic moment,if the frequency of revolution of electron is `6.8

2 Answers 8 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`I=q/t=e/t=(e v)/(2 pi r)`
`= (1.6xx10^(-19)xx2.18xx10^(6))/(6.28xx0.53xx10^(-10))`
`=1.048 xx 10^(-3)A`

8 views Answered 2023-02-05 15:29