a proton enters a perpendicular magnetic field of intensity b with speed v the proton moves along a circular path of radius r if a deuteron enter into the same magnetic field with same speed the radius of the circular trajectory will be

Question

a proton enters a perpendicular magnetic field of intensity b with speed v the proton moves along a circular path of radius r if a deuteron enter into the same magnetic field with same speed the radius of the circular trajectory will be

a proton enters a perpendicular magnetic field of intensity 'B' with speed 'v ' the proton moves along a circular path of radius R. if a deuteron enter into the same magnetic field with same speed the radius of the circular trajectory will be

a)R

b)less than R

c)more than R

d)cannot be said

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

General formula R = mv/qB

When a proton enter a perpendicular magnetic field intensity B and speed v. The proton move along a circular path of radius R.

R = mv/qB

where m = mass of proton

v = speed

q = charge

B = field intensity

If a deuteron enter into the same magnetic field with same speed the radius of the circular trajectory will same R, because deuteron is an isotope of hydrogen with 1 neutron and 1 proton. We neglect neutron because it is neutral.

Option (a) R is correct.