A proton and an `alpha` particle accellerated throught the same potential differenc e enter a region of uniform magnetic field normally if the radius of the proton orbit is 10 cm ten radius of `alpha` particle is
A. `10 cm`
B. `10sqrt(2)cm`
C. `20cm`
D. `5sqrt(2)cm`

4 views

1 Answers

Correct Answer - B
Radius of path `r_(1)=(1)/(B)sqrt(2mv)/(q)`
`therefore (r_(alpha))/(r_(p))=sqrt(m_(alpha))/(m_(p))sqrt(q_(p))/(q_(alpha))`
`rarr (r_(alpha))/(10)=sqrt(4/2) rarr r_(alpha) =10sqrt(2) cm`

4 views

Related Questions