A proton , a deuteron and an `alpha`-particle enter a magnetic field perpendicular to field with same velocity. What is the ratio of the radii of circ

Question

A proton , a deuteron and an `alpha`-particle enter a magnetic field perpendicular to field with same velocity. What is the ratio of the radii of circ

A proton , a deuteron and an `alpha`-particle enter a magnetic field perpendicular to field with same velocity. What is the ratio of the radii of circular paths ?
A. `1:2:2`
B. `2:1:1`
C. `1:1:2`
D. `1:2:1`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

A proton, a deuteron and an `alpha`-particle with the same KE enter a region of uniform magnetic field, moving at right angles to B. What is the ratio

2 Answers 4 Views

What uniform magnetic enter a magnetic field applied perpendicular to a beam of electrons moving at `1.3xx10^(6) ms^(-1)` is required to make the elec

2 Answers 5 Views

An electron and a proton enter a magnetic field perpendicularly. Both have same kinetic energy. Which of the following is true

2 Answers 4 Views

A proton and an `alpha` particle accellerated throught the same potential differenc e enter a region of uniform magnetic field normally if the radius

2 Answers 4 Views

a proton enters a perpendicular magnetic field of intensity b with speed v the proton moves along a circular path of radius r if a deuteron enter into the same magnetic field with same speed the radius of the circular trajectory will be

2 Answers 5 Views

A proton and a deuteron both having the same kinetic energy enter perpendicularly in to uniform magnetic field B for motion of proton and deuteron on

2 Answers 4 Views

Calculate the binding energy of an `alpha`-particle. Given that mass of proton = 1.0073 u, mass of neutron = 1.0087 u, and mass of `alpha`- particle =

2 Answers 4 Views

A deuteron of kinetic energy 25ke V is describing a circular orbit of radius 0.5 m in a plane perpendicular to magnetic field `vec(B)`. The kinetic en

2 Answers 5 Views

A `2MeV` proton is moving perpendicular to a uniform magnetic field `2.5` tesla. The force on the proton is

2 Answers 4 Views

A proton an an `alpha-`particle, moving with the same velocity, enter a uniform magnetic field, acting normal to the plane of their motion. The ratio

2 Answers 5 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`r prop(m)/(v)`
`therefore r_p :r_d:r_alpha = (m_p)/(q_p):(m_d)/(q_d):(m_alpha)/(q_alpha)`
`= (m_p)/(q_p):(2m_p)/(q_p):(4m_p)/(2q_p)`
`=1:2:2`.

4 views Answered 2023-02-05 15:29