A `2MeV` proton is moving perpendicular to a uniform magnetic field `2.5` tesla. The force on the proton is
A. `8xx10^-10N`
B. `4xx10^-10N`
C. `6xx10^-10N`
D. `8xx10^-12N`

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1 Answers

Correct Answer - D
`E_k=(1)/(2)mv^2{v=2xx10^7 m//s)`.
`F=qv Bsin 90 =8xx10^-12N`.

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