A deuteron of kinetic energy 25ke V is describing a circular orbit of radius 0.5 m in a plane perpendicular to magnetic field `vec(B)`. The kinetic en

A deuteron of kinetic energy 25ke V is describing a circular orbit of radius 0.5 m in a plane perpendicular to magnetic field `vec(B)`. The kinetic energy of the proton that describes a circular orbit of radius . 0.5 m in the same plane with the same `vec(B)` is
A. 200keV
B. 50keV
C. 100keV
D. 25keV

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - B
`E=(q^2 B^2r^2)/(2m)`
`therefore (E_p)/(E_d)=((q_d)/(q_p))^2(m+p)/(m_d)=2`
`therefore E_p=2 E_d=2xx25=50k e V`

5 views Answered 2023-02-05 15:29

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