In a hydrogen atom the electrons revolves round the nucleus `6.8xx10^(15)` times per second in a n orbit of radius 0.53 Å.Determine its equivalent mag

Question

In a hydrogen atom the electrons revolves round the nucleus `6.8xx10^(15)` times per second in a n orbit of radius 0.53 Å.Determine its equivalent mag

In a hydrogen atom the electrons revolves round the nucleus `6.8xx10^(15)` times per second in a n orbit of radius 0.53 Å.Determine its equivalent magnetic moment`(e=16xx10^(-19)C)`
A. `9.1xx10^(-24)Am^(2)`
B. `9.3xx10^(-24)Am^(2)`
C. `9.0xx10^(-24) Am^(2)`
D. `9.6xx10^(-24)Am^(2)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`M=IA=(ev)/(2pir)A=e.f.A.=e.f.pi r^(2)`
`=1.6xx10^(-19)xx6.8xx10^(15)3.14xx(0.53xx10^(-10))^(2)`
`=9.596xx10^(-24)~~9.6xx10^(-24)Am^(2)`

4 views Answered 2023-02-05 15:29