A `H_(2)` atom consits of a proton and an electron that revolves in a circular orbit around the proton with a radius of `5.3xx10^(-9)cm`. If the electron moves so that its centrifugal force is just equal to the electrostatic force then the speed is
A. `22xx10^(7)m//s`
B. `2.2xx10^(6)m//s`
C. `3.2xx10^(7)m//s`
D. `3.2xx10^(7)m//s`

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1 Answers

Correct Answer - B
`(mv^(2))/r=1/(4piin_(0))(q_(1)q_(2))/r^(2)`
`therefore" "v=2.2xx10^(6)m//s`

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