A galvanometer of resistance `(G) 10 Omega` and a series resistance `250 Omega` is used to convert it into a voltmeter of 2 V reading. The current pas

Question

A galvanometer of resistance `(G) 10 Omega` and a series resistance `250 Omega` is used to convert it into a voltmeter of 2 V reading. The current pas

A galvanometer of resistance `(G) 10 Omega` and a series resistance `250 Omega` is used to convert it into a voltmeter of 2 V reading. The current passing through the voltmeter is nearly
A. 0.0077 m A
B. 0.077 m A
C. `0.77 m A
D. 7.7 m A

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`I_g=(V)/(R+G)=(2)/(250+10)=7.7m A` .

4 views Answered 2023-02-05 15:29