A galvanometer has a resistance `G Omega`. It is shunted by a resistance of `S Omega`. How much resistance should be added in series so that the main

A galvanometer has a resistance `G Omega`. It is shunted by a resistance of `S Omega`. How much resistance should be added in series so that the main current in the curcuit remains unchanged ?
A. `(S)/(S+G)`
B. `(G)/(G+S)`
C. `(G^2)/(G+S)`
D. `(SG)/(G+S)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - C
As range of ammeter increases the value of shunt decreases.

4 views Answered 2023-02-05 15:29

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