If galvanometer is shunted by `1//n^(th)` of its value, then what fraction of the current passes through the galvanometer ?
A. `1//n`
B. `n`
C. `1//(n+1)`
D. `1//(n-1)`

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1 Answers

Correct Answer - C
`V_g=I_g G therefore G=V_g//I_g=50Omega`
`S=((I_g)/(I-I_g))G=((0.015)/(25-0.015))xx50=0.03Omega`

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