The current sensitivity of a galvanometer is x div/m A and voltage sensitivity is y div/V . The resistance of galvanometer is G. Then relation between
The current sensitivity of a galvanometer is x div/m A and voltage sensitivity is y div/V . The resistance of galvanometer is G. Then relation between x and y is
A. `G=(x)/(y)xx10^3`
B. `G=(y)/(x)`
C. `G=(x)/(y)`
D. `y=Gxx10^3`
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Correct Answer - A
`S_i=x " div"//mA,S_V=y" div"//V,G=?`
`S_V=(S_i)/(G)therefore G=(S_i)/(S_V)`
`therefore G=(x xx10^3)/(y)`
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