A voltmeter has a resistance of `50 Omega` is connected across a cell of e.m.f. 2V and internal resistance `10 Omega`. The reading of voltmeter is
A. 1.667V
B. 16.7V
C. 167V
D. 0.167V

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1 Answers

Correct Answer - A
`V=I R=((E)/(R+r))R=((2)/(50+10))50=1.667 V`

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