If the amount of heat given to a system is 40 J and the amount of work done on the system is 15 J then the change in internal energy is
A. 50 J
B. `-50J`
C. `30J`
D. `55J`

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1 Answers

Correct Answer - D
`dQ=du+domega`
`du=dQ-(domega)`
`=40+15=55J`.

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