A system absorbs 100 cal of heat and does an external work of 150 J. if J=4.2 J/cal the change in internal energy is
A. 420 J
B. 270 J
C. 250 J
D. 150 J

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1 Answers

Correct Answer - B
`DeltaQ=100xx4.2`
`=420J`
`DeltaW=150J`
`DeltaU=DeltaQ-DeltaW`
`=420-150=270J`.

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