What tension should be there in a string of length 0.8m and of mass `5xx10^(-3) kg`, if it vibrates with fundamental frequency of 100 Hz?

Question

What tension should be there in a string of length 0.8m and of mass `5xx10^(-3) kg`, if it vibrates with fundamental frequency of 100 Hz?

What tension should be there in a string of length 0.8m and of mass `5xx10^(-3) kg`, if it vibrates with fundamental frequency of 100 Hz?
A. 100N
B. 160N
C. 140N
D. 120N

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

A guitar string is 100 cm long and has a fundamental frequency of 125 Hz. Where should it be pressed to produce a fundamental frequency of 200 Hz.

2 Answers 7 Views

A string of mass 0.2 kg/m and length l= 0.6 m is fixed at both ends and streteched such that it has a tension of 80 N. the string vibrates in 3 segmen

2 Answers 4 Views

A segment of wire vibrates with fundamental frequency of 40 Hz under a tension of 9 kg-wt. Then, tension at which the fundamental frequency of the sam

2 Answers 4 Views

A wire under tension vibrates with a fundamental frequency of 600 Hz. If the length of the wire is doubled, the radius is halved and the wire is made

2 Answers 4 Views

A wire under a tension vibrates with fundamental frequency of 256 Hz . What should be the fundamental frequency of the wire if its length is half, thi

2 Answers 5 Views

The fundamental frequency of vibration of a wire fo certain length is 200 Hz. What will be the fundamental frequency of vibration, if the tension is m

2 Answers 4 Views

A string of length 0.5m and linear density `10^(-4)` kg/m is stretched under a tension of 100 N. If the frequency of the vibration of the string is 40

2 Answers 5 Views

The string of monochord , vibrates 100 times a second. Its length is doubled and its tension is altered unitl it makes 150 vib/s . What is the ratio o

2 Answers 6 Views

A wire under tension vibrates with a frequency of 450Hz. What would be the fundamental frequency, if the wire were half as long, twice as thick and un

2 Answers 4 Views

The stirng stretched by tension T and length L vibrates in resonance with a tuning fork of frequency n. the tension in the stretched string is increas

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`n=(1)/(2l) sqrt(T/m) therefore n^2 = (1)/(4l^2) T/m`
`therefore T= 4n^2l^2m`
`=(4xx10^(4)xx0.6xx5xx10^(-3))/(0.8) = 160N`

4 views Answered 2023-02-05 15:29