A segment of wire vibrates with fundamental
frequency of 40 Hz under a tension of 9 kg-wt. Then,
tension at which the fundamental frequency of the
same wire becomes 900 Hz is
A. 36 kg-wt
B. 27 kg-wt
C. 18 kg-wt
D. 72 kg-wt

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1 Answers

Correct Answer - a
Fundamental frequency, `n=1/(2l)sqrt(T/m)and nprop sqrt(T)`
`therefore n_(1)/n_(2)=sqrt(T_(1)/T_(2))rArr 450/900=sqrt(9/T_(2))`
`T_(2)=36` kg-wt

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