A string of length 0.5m and linear density `10^(-4)` kg/m is stretched under a tension of 100 N. If the frequency of the vibration of the string is 40

Question

A string of length 0.5m and linear density `10^(-4)` kg/m is stretched under a tension of 100 N. If the frequency of the vibration of the string is 40

A string of length 0.5m and linear density `10^(-4)` kg/m is stretched under a tension of 100 N. If the frequency of the vibration of the string is 4000 Hz, how many loops are formed on the string?
A. 1
B. 4
C. 2
D. 6

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`n=(P)/(2l) sqrt(T/m) therefore P=(4000xx2xx0.5)/(10^3)=4`

5 views Answered 2023-02-05 15:29