A wire is stretched by `2xx10^(-2)`m due to the force of 10 N. Then the amount of work done to stretch the wire to a displacement of `4xx10^(-2)`m is

Question

A wire is stretched by `2xx10^(-2)`m due to the force of 10 N. Then the amount of work done to stretch the wire to a displacement of `4xx10^(-2)`m is

A wire is stretched by `2xx10^(-2)`m due to the force of 10 N. Then the amount of work done to stretch the wire to a displacement of `4xx10^(-2)`m is
A. 0.04 J
B. 0.4 J
C. 40 J
D. 400 J

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`W_(1) =(1)/(2) Fl=(1)/(2)xx10 xx 2 xx 10^(-2) =0.1J`
`(W_(2))/(W_(1))=((l_(2))/(l_(1)))^(2)=((4xx10^(-2))/(2xx10^(-2)))^(2)=4`
`W_(2)=4W_(1)`
`=4xx0.1=0.4J`.

5 views Answered 2023-02-05 15:29