A steel wire of length 2.5 m and area of cross section `1.25 mm^(2)`, when it is stretched by a force of 40 N and Y for steel is `2xx10^(11)N//m^(2)`.

Question

A steel wire of length 2.5 m and area of cross section `1.25 mm^(2)`, when it is stretched by a force of 40 N and Y for steel is `2xx10^(11)N//m^(2)`.

A steel wire of length 2.5 m and area of cross section `1.25 mm^(2)`, when it is stretched by a force of 40 N and Y for steel is `2xx10^(11)N//m^(2)`. The extension produced in a steel wire is
A. 0.4 mm
B. 0.4 cm
C. 4 mm
D. 4 cm

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`y=(FL)/(Al)`
`therefore l=(40xx2.5)/(2xx10^(11)xx1.25xx10^(-6))=0.4 mm. `

6 views Answered 2023-02-05 15:29