A wire of resistance `4 Omega` is stretched to twice its original length. The resistance of stretched wire would be

Question

A wire of resistance `4 Omega` is stretched to twice its original length. The resistance of stretched wire would be

A wire of resistance `4 Omega` is stretched to twice its original length. The resistance of stretched wire would be
A. `4Omega`
B. `8Omega`
C. `16Omega`
D. `2Omega`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`(R_(2))/(R_(1))=((l_(2))/(l_(1)))^(2)`
`R_(2)=((2l_(1))/(l_(1)))^(2)R_(1)=4xx4=16Omega`.

4 views Answered 2023-02-05 15:29