The resistance of a wire is `2 Omega`. The wire is stretched to doubel its length. Now the resistance of the wire will become
A. `0.25R`
B. `0.5R`
C. `2R`
D. `4R`

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1 Answers

Correct Answer - D
`R_(2)=n^(2)R_(1)=2^(2)xxR=4 R`

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