A wire of resistance `4 Omega` is stretched to four times of its original length resistance of wire now becomes

Question

A wire of resistance `4 Omega` is stretched to four times of its original length resistance of wire now becomes

A wire of resistance `4 Omega` is stretched to four times of its original length resistance of wire now becomes
A. `4Omega`
B. `8Omega`
C. `64Omega`
D. `16Omega`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`R_(1)=4 Omega, l_(2)=4 l_(1), R_(2)=?`
`(R_(2))/(R_(1))=((l_(2))/(l_(1)))^(2)`
`:.R_(2)=((4l_(1))/(l_(1)))^(2)xxR_(1)=16xx4=64Omega`.

5 views Answered 2023-02-05 15:29