The phase angle between the two projections of uniform circular motion on any two mutually perpendicular diameter is

Question

The phase angle between the two projections of uniform circular motion on any two mutually perpendicular diameter is

The phase angle between the two projections of uniform circular motion on any two mutually perpendicular diameter is
A. zero
B. `pi//2`
C. `3pi//4`
D. `pi`

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`x=Asinomegat" ... (i)"`
`y=Asin(omegat+(pi)/(2))`
`=Acosomegat" ... (ii)"`
Squaring and adding equation (i) and (ii),
`x^(2)+y^(2)=A^(2)(sin^(2)omegat+cos^(2)omegat)`
`x^(2)+y^(2)=A^(2)`
This is standard equation of circle.

7 views Answered 2023-02-05 15:29