If a uniform solid sphere of diameter 0.2 m and mass 10 kg is rotated about its diameter with an angular velocity of 2 rad/s, then the its angular momentum in kg `m^(2)//s` will be
A. 0.01
B. 0.02
C. 0.08
D. 0.04

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1 Answers

Correct Answer - C
`L = I omega = (2)/(5)MR^(2)omega =(2)/(5)xx10xx10^(-2)xx2`
`= 0.08 kgm^(2)//s`.

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