If an electric iron of 1200 W is used for 30 minutes everyday, find electric energy consumed in the month of April.

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1 Answers

P = 1200 / 1000 = 1.2 kW 

t = 30 /60 =0.5h 

E = Power × time × days 

= 1.2×.5×30 

= 18 kW h

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