1 Answers
Option 3 : Rs. 100000
Value of the machine in the book of D (Cost price for D – 20% of cost price) = Rs. 105600
Cost price for D = (100 × 105600)/80
⇒ 1056000/8
⇒ 132000
Accordingly, Selling price for C = 132000
Selling price for C = Cost + 10%
Cost price for C = (100 × 132000)/110
⇒ 1320000/11
⇒ 120000
As we know, Rs. 8910 is spent by C after purchasing it from A
Accordingly, Selling Price for A = 120000 – 8910
⇒ 111090
Selling price for A = (Cost price – Depreciation @8%) + 5%
Accordingly, Cost price – Depreciation @8% for A = (100 × 111090)/105
⇒ 11109000/105
⇒ 105800
Cost price = (100 × 105800)/92
⇒ 10580000/92
⇒ 115000
Accordingly, Selling price for B = 115000
Selling price = Cost price + 15%
Cost price for B = (100 × 115000)/115
⇒ 11500000/115
⇒ 100000
∴ Actual cost price of the machine at which it is purchased by B is Rs.100000