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Option 1 : 10 hours
Let t be the usual time taken.
At a speed of 8kmph he takes (t + 4)hours
At a speed of 14kmph he takes (t – 2)hours
Distance travelled is same
∴ 8(t + 4) = 14(t – 2)
∴ 8t + 32 = 14t – 28
∴ 6t = 60
∴ t = 10 hours
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