In the following question, two statements are numbered as A and B. On solving these statements, we get quantities A and B respectively. Solve both quantities and choose the correct option. Quantity I: Pipe A alone can fill the tank in 15 hours while pipe B alone can empty the tank in 5 hours. There is a leakage at the bottom which also alone can empty the tank in 4 hours. When pipe A and Pipe B are open simultaneously then in how many hours the tank gets empty Quantity II: 25 men can complete the work in 20 hours and 30 women can complete the work in 15 hours. If 15 men work for 10 hours then stopped working then remaining work gets completed by all 30 women. In what time total works get completed?

Option 3 : Quantity I < Quantity II

Quantity I:

Pipe A's 1 hour's work = 1/15

Pipe B's 1 hour's work = 1/5

Leakage 1 hour's work = ¼

Pipe (A + B) and leakage 1 hours work = 1/15 – 1/5 – ¼ = -23/60

The tank will get empty in 60/23 hours.

Quantity II:

1 men 1 hour's work = 1/(20 × 25)

1 women 1 hour's work = 1/(30 × 15)

15 men 10 hours work = 15 × 1/(20 × 15) × 10 = ½

Remaining work = ½

30 women work = 30/(30 × 15) = 1/15

Total time in which 30 women can complete the half of the work = ½ × 15 = 15/2 hours.

Total works gets completed in = 10 + 15/2 = 35/2 hours

So, we can observe Quantity I < Quantity II.