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Option 2 : Quantity A < Quantity B

Quantity A:

Time taken by A to fill the tank = x hours

⇒ Tank filled by A in 1 hour = 1/x

Time taken by B to fill the tank = (x + 7) hours

⇒ Tank filled by B in 1 hour = 1/(x + 7)

Two outlet pipes can empty the tank in 3.5 hours and their efficiency is same

⇒ C + D = 1/3.5

⇒ 2C = 1/3.5      ----(C = D)

⇒ C = 1/7

∴ C = D = 7 hours

Working together they can fill the tank in 2 hours

⇒ 1/A + 1/B – 1/C – 1/D = 1/2

⇒ 1/x + 1/(x + 7) – (1/7) – (1/7) = 1/2

⇒ 1/x + 1/x + 7 = 1/2 – 1/7 – 1/7

⇒ (2x + 7)/(x)(x + 7) = 3/14

⇒ 3x2 – 7x – 98 = 0

⇒ 3x2 – 21x + 14x – 98 = 0

⇒ 3x(x – 7) + 14(x – 7) = 0

⇒ x = 7, -14/3

 Rejecting -14/3 as work can’t be negative

∴ Time taken by A to fill the tank alone = 7 hrs

Quantity B:

 The ratio of efficiencies of two pipes A and B is in the ratio 3 ∶ 2

The ratio of efficiencies of two pipes B and C is in the ratio 1 ∶ 3

Equating the coefficient of B in both the ratios

The ratio of efficiencies of two pipes B and C = 2 ∶ 6

∴ Ratio of efficiency of A, B and C = 3 ∶ 2 ∶ 6

Let the time taken by A, B and C be 3x, 2x and 6x

Working together they can fill the tank in 7.5 hours

⇒ 1/3x + 1/2x – 1/6x = 1/7.5

⇒ 4/6x = 1/7.5

⇒ x = 5

∴ Time taken by A to fill the tank alone = 5 × 3 = 15 hours

Hence Quantity A < Quantity B
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