Two pipes A and B can fill an empty tank in 8 hours and 12 hours respectively. A third pipe C can empty the full tank in 15 hours. When the tank is empty, pipes A and B are opened and after 2 hours pipe A is closed and pipe C is opened. In how many hours, the tank will be completely filled?

37
53/9
17/3
52/9

LohaHridoy

6 views

2025-01-04 04:42

1 Answers

AhmedNazir

Option 1 : 37

Given:

Pipe A can fill a tank in 8 hours

Pipe B can fill a tank in 12 hours

Pipe C alone can empty the full tank in 15 hours.

A and B are opened together for 2 hours and then C is also opened

Formula used:

Time taken by A + B + C = Remaining work/Efficiecy.(A + B + C)

Calculation:

According to the question;

	Time	Total	Efficiency
A	8 hours	120(LCM)	+ 15 w/hrs
B	12 hours		+ 10 w/hrs
C	15 hours		- 8 w/hrs

A + B = 25 w/hrs

They work for 2 hours,

Toatal work done = 25 × 2 = 50 units

Remaining work = 120 - 50 = 70 units

Now, A is closed and B and C work,

B + C = 10 + (-8) = 2 w/hrs

Time Taken = 70/2 = 35 hours

Total Time Taken to fill the tank = 35 + 2 = 37 hrs.

∴ Total Time Taken to fill the tank is 37 hrs.

6 views Answered 2022-09-04 04:29

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