Two trains whose lengths are 100 meters and 200 meters respectively run from A to B at 10 AM and 12 AM respectively and their speed is 18 km/h and 36 km/h respectively. Ram travels in a train of short length. If C is a station between A and B, here Ram's friend board in the high speed train and both meet at that place, where the high speed train crosses the low speed train. If the short length train reached point C at 12 o'clock, then find when will the two friends meet?

Question

Two trains whose lengths are 100 meters and 200 meters respectively run from A to B at 10 AM and 12 AM respectively and their speed is 18 km/h and 36 km/h respectively. Ram travels in a train of short length. If C is a station between A and B, here Ram's friend board in the high speed train and both meet at that place, where the high speed train crosses the low speed train. If the short length train reached point C at 12 o'clock, then find when will the two friends meet?

2:10 PM
2:00 PM
2:20 PM
2:15 PM
None of these

LohaHridoy

5 views

2025-01-04 04:42

1 Answers

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AhmedNazir · Accepted Answer · 2022-09-04T04:29:57+06:00

Option 2 : 2:00 PM

Given:

Length of 1^st train = 100 meter

Length of 2^nd train = 200 meter

Speed of 1^st train = 18 km/h

Speed of 2^nd train = 36 km/h

Concept used:

1.) Relative speed is defined as the speed of a moving object with respect to another.

2.) When two objects are moving in the same direction, relative speed is calculated as their difference.

3.) m/s = (km/h) × (5/18)

Formula used:

Speed = Distance/time

Distance = Speed × time

Relative speed when moving in same direction = a – b

Calculations:

Train 1^st reaches at point C on 12 AM

Time taken by 1^st train to reach at C = 12 AM – 10 AM = 2 hours

Distance between A to C = 18 × 2 = 36 km = 36000 meter

Total distance which is covered by 2^nd train to cross the train = 200 + 36000 + 100 = 36300 m

Relative speed of both the trains = a – b = 36 – 18 = 18 km/h = 18 × (5\18) = 5 m/s

Total time taken by 2^nd train to cross the 1^st train = Distance/speed = 36300/5 = 7260 second

Time taken in hours = 7260/3600 = 2.01 hours ≈ 2 hours

∴ Time to meet of both the friends = 12 AM + 2 hours = 2:00 PM