1 Answers

Option 1 : D

Calculation:

Total number of students appeared = 1200

Numbers of students appeared in the examination from institutes A = 72° 

⇒ (72/360 × 1200) 

⇒ 240

Numbers of students appeared in the examination from institutes B = 54° 

⇒ (54/360 × 1200) 

⇒ 180

Numbers of students appeared in the examination from institutes C = 90° 

⇒ (90/360 × 1200) 

⇒ 300

Numbers of students appeared in the examination from institutes D = 105°

⇒ (105/360 × 1200) 

⇒ 350

Numbers of students appeared in the examination from institutes E = 39°

⇒ (39/360 × 1200) 

⇒ 130

Now,

Total number of students passed = 900

Numbers of students passed in the examination from institutes A = 15%

⇒ (900 × 15/100)

⇒ 135

Numbers of students passed in the examination from institutes B = 18%

⇒ (900 × 18/100)

⇒ 162

Numbers of students passed in the examination from institutes C = 30%

⇒ (900 × 30/100)

⇒ 270

Numbers of students passed in the examination from institutes D = 28%

⇒ (900 × 28/100)

⇒ 252

Numbers of students passed in the examination from institutes E = 9%

⇒ (900 × 9/100)

⇒ 81

The percentage of students of institutes A passed to the students who appeared from that institute = (135/240 × 100)

⇒ 56.25%

The percentage of students of institutes B passed to the students who appeared from that institute = (162/180 × 100)

⇒ 90%

The percentage of students of institutes C passed to the students who appeared from that institute = (270/300 × 100)

⇒ 90%

The percentage of students of institutes D passed to the students who appeared from that institute = (252/350 × 100)

⇒ 72%

The percentage of students of institutes E passed to the students who appeared from that institute = (81/130 × 100)

⇒ 62.30%

Now,

We can see that the percentage of B and C is same which is also the highest = 90%

So, the second highest percentage of students who passed to the  students who appeared is from institute D = 72%

∴ The required answer is Institute D

5 views

Related Questions