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x+1/x =3 হলে, x^4+1/x^4 =47 হবে, 119 নয়। বামপক্ষ =x^4+1/x^4 = (x^2)^2+(1/x^2)^2 =(x^2+1/x^2)^2-2 ={(x+1/x)^2-2}^2-2 ={(3)^2-2}^2-2 [মান বসিয়ে] = (9-2)^2-2 =7^2-2 =49-2 =47. বামপক্ষ = ডানপক্ষ। (প্রমাণিত)
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বামপক্ষ= (X^2)^2+(1/x^2)^2 =(x^2+1/x^2)^2-2x^2*1/x^2 ={(x+1/x)^2-2x*1/x}^2-2 =(3^2-2)^2-2 =(9-2)^2-2 =7^2-2 =49-2 =47 ভাই এটি তো ৪৭ আসে আপনি হয়ত কথাও ভুল করেছেন
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