m1(u1-v1)=m2(v2-u2) [e:1] m1(u1^2-v1^2)=m2(v2^2-u2^2) [e:2] dividing e2 by e1....... u1+v1=v2+u2 so, v1=v2+u2-u1 and, v2=v1+u1-u2 Putting the value of v2 in e1 *m1(u1-v1)=m2(v1+u1-u2-u2) *m1(u1-v1)=m2(v1+u1-2u2) *m1u1-m1v1=m2v1 +m2u1-2m2u2 *m1u1-m2u1+2m2u2 =m1v1+m2v1 *m1v1+m2v1=m1u1-m2u1+2m2u2 *v1(m1+m2)=u1(m1-m2)+2m2u2 so, v1=u1(m1-m2) +2m2u2/m1+m2 [solved] NB: v2 o eibhabe ber kora jabe