A petrol car is hired for 6 days. Expense is Rs. 10 more on each day than the expenses made on the previous day. What was the total expenditure incurred in 6 days? Statement I: One-third of the total expense was made in the first 3 days. Statement II: Expenses on the 5th day is twice the expenses on 2nd day.
A petrol car is hired for 6 days. Expense is Rs. 10 more on each day than the expenses made on the previous day. What was the total expenditure incurred in 6 days? Statement I: One-third of the total expense was made in the first 3 days. Statement II: Expenses on the 5th day is twice the expenses on 2nd day. Correct Answer Either statement I or statement II alone is sufficient to answer the question.
From question statement
If expenses on 1st day = Rs. x,
Then the expenses on each subsequent day will be Rs. (x + 10), (x + 20), (x + 30), (x + 40), (x + 50).
Total expenses for 6 days = (6x + 150) ---- (1)
From statement I:
One-third of total expenses was made in the first 3 days.
(x + x + 10 + x + 20) = (6x + 150)/3
⇒ 3x + 30 = 2x + 50
⇒ x = 20
⇒ Total expenditure incurred in 6 days = 120 + 150 = Rs. 270
From statement II:
Expense on the 5th day is twice the expenses on 2nd day.
(x + 40) = 2 × (x + 10)
⇒ x = 20
⇒ Total expenditure incurred in 6 days = 120 + 150 = Rs. 270
∴ Either statement I or statement II alone is sufficient to answer the question.