Can 1 contains a mixture of milk and water in ratio 7 : 9 and Can 2 contains a mixture of milk and water in ratio 4 : 3. In what ratio should Can 1 and 2 be mixed to obtain a milk in the mixture as 50%?  

Can 1 contains a mixture of milk and water in ratio 7 : 9 and Can 2 contains a mixture of milk and water in ratio 4 : 3. In what ratio should Can 1 and 2 be mixed to obtain a milk in the mixture as 50%?   Correct Answer 8 : 7

Given:

Milk and Water in Can 1 = 7 : 9

Milk and Water in Can 2 = 4 : 3

In final mixture milk is 50%

Calculation:

In Can 1, 

Milk : Water = 7 : 9

⇒ Milk in the total Can 1 = 7/(7 + 9)

⇒ Milk in the total Can 1 =  7/16

In Can 2,

Milk : Water = 4 : 3 

⇒ Milk in the total Can 2 = 4/(4 + 3)

⇒ Milk in the total Can 2 =  4/7

In final milk is 50% then,

Water is final mixture is 50%

⇒ Ratio of milk and water in final mixture = 1 : 1

⇒ Milk in the final mixture = 1/(1 + 1)

⇒ Milk in the final mixture = 1/2

By mixture and allegation,

⇒ [ alt="F1 Mohd.S 10-05-21 Savita D1" src="//storage.googleapis.com/tb-img/production/21/05/F1_Mohd.S_10-05-21_Savita_D1.png" style="width: 156px; height: 193px;">

⇒ (4/7 – 1/2) : (1/2 – 7/16)

⇒ 1/14 : 1/16

⇒ 16 : 14

⇒ 8 : 7

∴ Can 1 and 2 be mixed in the ratio 8 : 7

Related Questions

Jar A comprises a mixture of milk and water in the ratio of 3 : 2 respectively. Another mixture of milk and water is added to jar A and the ratio of milk and water in the resultant mixture changes. What was the initial quantity of mixture present in Jar A? I. The ratio of milk and water in the mixture that was added to Jar A was 2 : 1 respectively. II. The ratio of the new quantities of milk and water in Jar A was 8 : 5 respectively. The quantity of water in the mixture added to jar A was 6 litre.