A mixture contains milk and water in the ratio (by volume) 5 : 3 and another mixture of the same volume as that of the former, contains water and milk in the ratio (by volume) 1 : 3. In what ratio, two mixture be mixed in order to obtain a new mixture consisting of milk and water in the ratio (by volume) 7 : 3?

A mixture contains milk and water in the ratio (by volume) 5 : 3 and another mixture of the same volume as that of the former, contains water and milk in the ratio (by volume) 1 : 3. In what ratio, two mixture be mixed in order to obtain a new mixture consisting of milk and water in the ratio (by volume) 7 : 3? Correct Answer 2 : 3

Amount of milk in first mixture = 5/8

⇒ Amount of milk in second mixture = 3/4

⇒ Amount of milk in the required solution = 7/10

By allegation method,

[ alt="F1 SSC MTS 13 August 2019 shift 2 Komal Q 26 - 50 sachin c D 1" src="//storage.googleapis.com/tb-img/production/20/03/F1_SSC_MTS_13_August_2019_shift_2_Komal%20Q_26%20-%2050_sachin%20c_D%201.PNG">

∴ The required ratio = 2/40 : 6/80 = 2 : 3

Related Questions

Jar A comprises a mixture of milk and water in the ratio of 3 : 2 respectively. Another mixture of milk and water is added to jar A and the ratio of milk and water in the resultant mixture changes. What was the initial quantity of mixture present in Jar A? I. The ratio of milk and water in the mixture that was added to Jar A was 2 : 1 respectively. II. The ratio of the new quantities of milk and water in Jar A was 8 : 5 respectively. The quantity of water in the mixture added to jar A was 6 litre.