In a society A the ratio of males and females is 8 ∶ 5 and in another society B the ratio of males and females is 7 ∶ 9. If the sum of the males in both the society is 52 and the number of females in  society B is 21 more than the number of female in society A. Find the number of men in both societies is what percentage of number of females in both the societies(approximate value).

In a society A the ratio of males and females is 8 ∶ 5 and in another society B the ratio of males and females is 7 ∶ 9. If the sum of the males in both the society is 52 and the number of females in  society B is 21 more than the number of female in society A. Find the number of men in both societies is what percentage of number of females in both the societies(approximate value). Correct Answer 102%

The ratio of males and females in society A is 8 ∶ 5

Let the number of males and females be 8x and 5x respectively

The ratio of males and females in society B is 7 ∶ 9

Let the number of males and females be 7y and 9y respectively 

∴ According to question

8x + 7y = 52      ----(i)

9y – 5x = 21      ----(ii)

Solving (i) and (ii) 

x = 3 and y = 4

∴ Males in both the societies = 52 (given)

Females in both the societies = 9y + 5x = 9 × 4 + 5 × 3 = 51

∴ Required percentage = (52/51) × 100 = 101.96% or 102%

∴ The number of men in both societies is 102% of number of females in both the societies

Related Questions

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