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A farmer divides the herd of n cows among his four sons in such a way that the first son gets half the herd, the second son gets one-fourth, the third son gets gets 1/5 share and the fourth son gets 7 cows. What is the value of n accordingly?

A farmer divides the herd of n cows among his four sons in such a way that the first son gets half the herd, the second son gets one-fourth, the third son gets gets 1/5 share and the fourth son gets 7 cows. What is the value of n accordingly? Correct Answer 140

Given:

Number of cow = n cows

First son gets = n/2 cows

Second son gets = n/4 cows

Third son gets = n/5 cows

Forth son gets = 7 cows

Calculation:

Sum of cows each son gets equals the total number of cows

(n/2) + (n/4) + (n/5) + 7 = n

⇒ 19n/20 + 7 = n

⇒ 19n + 7 × 20 = n20

⇒ n = 140

∴ The value of n is 140

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