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In a 500 meters race, X runs at a speed of 20 m/sec. If X gives Y a start of 50 meters and still beats him by 50 seconds, what will be the speed of B? A. Half of the three-fifth of the speed of X B. 8 m/sec C. 5 m/sec D. (2/5) of 10

In a 500 meters race, X runs at a speed of 20 m/sec. If X gives Y a start of 50 meters and still beats him by 50 seconds, what will be the speed of B? A. Half of the three-fifth of the speed of X B. 8 m/sec C. 5 m/sec D. (2/5) of 10 Correct Answer A

Given:

Distance of the race track = 500 meters

Speed of X = 20 m/sec

Calculation:

Time taken by X to complete the 500 meters = 500/20 = 25 sec

⇒ Distance covered by Y in (50 + 25) sec = 500 – 50 = 450 meters

⇒ Speed of Y = 450/75 = 6 m/sec

A. Half of the three-fifth of the speed of X

Half of the three-fifth of the speed of X = (1/2) of (3/5) of 20

⇒ (3/10) × 20

⇒ 6 m/sec

∴ A is correct.

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