In 1000 meters race A beats B by 70 meters and B beats C by 300 meters. In the same race, by how many meters does A beats C? A. 20% of 1750 B. 450 C. 700 D. (7/5) of 250

In 1000 meters race A beats B by 70 meters and B beats C by 300 meters. In the same race, by how many meters does A beats C? A. 20% of 1750 B. 450 C. 700 D. (7/5) of 250 Correct Answer A and D

Given:

Length of the race track = 1000 meter

Calculation:

A beats B by 70 meters

Distance traveled by A = 1000 m

⇒ Distance travelled by B = 1000 – 70 = 930 m

B beats C by 90 meters

Distance traveled by B = 1000 m

⇒ Distance travelled by C = 1000 – 300 = 700 m

In a 1000 m race ratio of distance travelled by A, B and C

A : B = 1000 : 930

⇒ A : B = 100 : 93

B : C = 1000 : 700

⇒ B : C = 10 : 7

Combining the ratio

⇒ A : B : C = 1000 : 930 : 651

Difference between distance travelled by A and C = 1000 – 651 = 349 meter

A. 20% of 1750

⇒ 20 × 1750/100

⇒ 350 meters

A is correct.

D. (7/5) of 250

⇒ 7 × 50

⇒ 350 metere

D is correct.

∴ A and D are correct.

Related Questions

The following question is accompanied by three statements (I), (II), and (III). You have to determine which statements(s) is/are sufficient/necessary to answer the questions. In a Kilometer race, by how many meters Raju beats Shaju? Statement I. In a kilometer race, Raju beats Laiju by 200 meters. Statement II. The ratio of the speed of Laiju and Shaju is 4 : 3. Statement III. In a kilometer race, Laiju beats Shaju by 300 meters.